2x^2-39x+169=0

Solution for 2x^2-39x+169=0 equation:

2x^2-39x+169=0

a = 2; b = -39; c = +169;
Δ = b2-4ac
Δ = -392-4·2·169
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-39)-13}{2*2}=\frac{26}{4}
=6+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-39)+13}{2*2}=\frac{52}{4}
=13
$